Js遍历数组

// for 循环遍历找最大最小
            function arrmax(params) {
                let max=[0]
                for (let i = 0; i < arr1.length; i++) {
                if(arr1[i]>max)
                max=arr1[i]
            }
            return max
            }
            let  arr1 = ['3','1','6','2','7']
            console.log( arrmax(arr1));


            function arrmin(params) {
                let min=[3]
                for (let i = 0; i < arr2.length; i++) {
                   if(arr2[i]<min){
                    min=arr2[i]
                   }
                    
                }
                return min
            }
            let arr2 = ['5','2','3','9','1']
            console.log(arrmin(arr2));

//通过数组的sort排序方法先把数据排序，再找出最大值和最小值
            let arrsort =   ['14','6','2','5','17','3','9','11']  
            arrsort.sort((a,b)=>a-b)  //从小到大排序
            console.log("最小"+arrsort[0]);
            console.log("最大"+arrsort[arrsort.length-1]);

 //Math
            let arrmath =['1','2','3','-5'] 
            console.log(Math.max(...arrmath)); 
            console.log(Math.min(...arrmath));